7(4c+1)-4c=13(3c-2)

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Solution for 7(4c+1)-4c=13(3c-2) equation: 



7(4c+1)-4c=13(3c-2)

We move all terms to the left:

7(4c+1)-4c-(13(3c-2))=0

We add all the numbers together, and all the variables

-4c+7(4c+1)-(13(3c-2))=0

We multiply parentheses

-4c+28c-(13(3c-2))+7=0



We calculate terms in parentheses: -(13(3c-2)), so:

13(3c-2)

We multiply parentheses

39c-26

Back to the equation:

-(39c-26)



We add all the numbers together, and all the variables

24c-(39c-26)+7=0

We get rid of parentheses

24c-39c+26+7=0

We add all the numbers together, and all the variables

-15c+33=0

We move all terms containing c to the left, all other terms to the right

-15c=-33

c=-33/-15

c=2+1/5

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