2=(x+25)(2x-30)

Solution for 2=(x+25)(2x-30) equation:

2=(x+25)(2x-30)

We move all terms to the left:

2-((x+25)(2x-30))=0

We multiply parentheses ..

-((+2x^2-30x+50x-750))+2=0


We calculate terms in parentheses: -((+2x^2-30x+50x-750)), so:

(+2x^2-30x+50x-750)

We get rid of parentheses

2x^2-30x+50x-750

We add all the numbers together, and all the variables

2x^2+20x-750

Back to the equation:

-(2x^2+20x-750)


We get rid of parentheses

-2x^2-20x+750+2=0

We add all the numbers together, and all the variables

-2x^2-20x+752=0

a = -2; b = -20; c = +752;
Δ = b2-4ac
Δ = -202-4·(-2)·752
Δ = 6416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6416}=\sqrt{16*401}=\sqrt{16}*\sqrt{401}=4\sqrt{401}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-4\sqrt{401}}{2*-2}=\frac{20-4\sqrt{401}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+4\sqrt{401}}{2*-2}=\frac{20+4\sqrt{401}}{-4}
$