(2x-3)=2(2x+3)=33

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Solution for (2x-3)=2(2x+3)=33 equation: 



(2x-3)=2(2x+3)=33

We move all terms to the left:

(2x-3)-(2(2x+3))=0

We get rid of parentheses

2x-(2(2x+3))-3=0



We calculate terms in parentheses: -(2(2x+3)), so:

2(2x+3)

We multiply parentheses

4x+6

Back to the equation:

-(4x+6)



We get rid of parentheses

2x-4x-6-3=0

We add all the numbers together, and all the variables

-2x-9=0

We move all terms containing x to the left, all other terms to the right

-2x=9

x=9/-2

x=-4+1/2

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