2=(3x+1)/(2x-1)

Solution for 2=(3x+1)/(2x-1) equation:

2=(3x+1)/(2x-1)

We move all terms to the left:

2-((3x+1)/(2x-1))=0


Domain of the equation: (2x-1))!=0

x∈R


We multiply all the terms by the denominator


-((3x+1)+2*(2x-1))=0


We calculate terms in parentheses: -((3x+1)+2*(2x-1)), so:

(3x+1)+2*(2x-1)

We multiply parentheses

(3x+1)+4x-2

We get rid of parentheses

3x+4x+1-2

We add all the numbers together, and all the variables

7x-1

Back to the equation:

-(7x-1)


We get rid of parentheses

-7x+1=0

We move all terms containing x to the left, all other terms to the right

-7x=-1

x=-1/-7

x=1/7