29x-2=(19x-13)+7x

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Solution for 29x-2=(19x-13)+7x equation: 



29x-2=(19x-13)+7x

We move all terms to the left:

29x-2-((19x-13)+7x)=0



We calculate terms in parentheses: -((19x-13)+7x), so:

(19x-13)+7x

We add all the numbers together, and all the variables

7x+(19x-13)

We get rid of parentheses

7x+19x-13

We add all the numbers together, and all the variables

26x-13

Back to the equation:

-(26x-13)



We get rid of parentheses

29x-26x+13-2=0

We add all the numbers together, and all the variables

3x+11=0

We move all terms containing x to the left, all other terms to the right

3x=-11

x=-11/3

x=-3+2/3

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