7(12+8t)-6=9(7t+2)+t

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Solution for 7(12+8t)-6=9(7t+2)+t equation: 



7(12+8t)-6=9(7t+2)+t

We move all terms to the left:

7(12+8t)-6-(9(7t+2)+t)=0

We add all the numbers together, and all the variables

7(8t+12)-(9(7t+2)+t)-6=0

We multiply parentheses

56t-(9(7t+2)+t)+84-6=0



We calculate terms in parentheses: -(9(7t+2)+t), so:

9(7t+2)+t

We add all the numbers together, and all the variables

t+9(7t+2)

We multiply parentheses

t+63t+18

We add all the numbers together, and all the variables

64t+18

Back to the equation:

-(64t+18)



We add all the numbers together, and all the variables

56t-(64t+18)+78=0

We get rid of parentheses

56t-64t-18+78=0

We add all the numbers together, and all the variables

-8t+60=0

We move all terms containing t to the left, all other terms to the right

-8t=-60

t=-60/-8

t=7+1/2

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