29=z/5+27

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Solution for 29=z/5+27 equation:



29=z/5+27
We move all terms to the left:
29-(z/5+27)=0
We get rid of parentheses
-z/5-27+29=0
We multiply all the terms by the denominator
-z-27*5+29*5=0
We add all the numbers together, and all the variables
-1z+10=0
We move all terms containing z to the left, all other terms to the right
-z=-10
z=-10/-1
z=+10

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