23x+3=3(2x+2)

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Solution for 23x+3=3(2x+2) equation: 



23x+3=3(2x+2)

We move all terms to the left:

23x+3-(3(2x+2))=0



We calculate terms in parentheses: -(3(2x+2)), so:

3(2x+2)

We multiply parentheses

6x+6

Back to the equation:

-(6x+6)



We get rid of parentheses

23x-6x-6+3=0

We add all the numbers together, and all the variables

17x-3=0

We move all terms containing x to the left, all other terms to the right

17x=3

x=3/17

x=3/17

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