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9x-4+2(2x+5)=-3(x+2)
We move all terms to the left:
9x-4+2(2x+5)-(-3(x+2))=0
We multiply parentheses
9x+4x-(-3(x+2))+10-4=0
We calculate terms in parentheses: -(-3(x+2)), so:We add all the numbers together, and all the variables
-3(x+2)
We multiply parentheses
-3x-6
Back to the equation:
-(-3x-6)
13x-(-3x-6)+6=0
We get rid of parentheses
13x+3x+6+6=0
We add all the numbers together, and all the variables
16x+12=0
We move all terms containing x to the left, all other terms to the right
16x=-12
x=-12/16
x=-3/4
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