29=11+3(2+s)

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Solution for 29=11+3(2+s) equation: 



29=11+3(2+s)

We move all terms to the left:

29-(11+3(2+s))=0

We add all the numbers together, and all the variables

-(11+3(s+2))+29=0



We calculate terms in parentheses: -(11+3(s+2)), so:

11+3(s+2)

determiningTheFunctionDomain
3(s+2)+11

We multiply parentheses

3s+6+11

We add all the numbers together, and all the variables

3s+17

Back to the equation:

-(3s+17)



We get rid of parentheses

-3s-17+29=0

We add all the numbers together, and all the variables

-3s+12=0

We move all terms containing s to the left, all other terms to the right

-3s=-12

s=-12/-3

s=+4

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