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3(2x-5)+6=4(2x-3)+3
We move all terms to the left:
3(2x-5)+6-(4(2x-3)+3)=0
We multiply parentheses
6x-(4(2x-3)+3)-15+6=0
We calculate terms in parentheses: -(4(2x-3)+3), so:We add all the numbers together, and all the variables
4(2x-3)+3
We multiply parentheses
8x-12+3
We add all the numbers together, and all the variables
8x-9
Back to the equation:
-(8x-9)
6x-(8x-9)-9=0
We get rid of parentheses
6x-8x+9-9=0
We add all the numbers together, and all the variables
-2x=0
x=0/-2
x=0
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