29=(x-2)(x+6)

Solution for 29=(x-2)(x+6) equation:

29=(x-2)(x+6)

We move all terms to the left:

29-((x-2)(x+6))=0

We multiply parentheses ..

-((+x^2+6x-2x-12))+29=0


We calculate terms in parentheses: -((+x^2+6x-2x-12)), so:

(+x^2+6x-2x-12)

We get rid of parentheses

x^2+6x-2x-12

We add all the numbers together, and all the variables

x^2+4x-12

Back to the equation:

-(x^2+4x-12)


We get rid of parentheses

-x^2-4x+12+29=0

We add all the numbers together, and all the variables

-1x^2-4x+41=0

a = -1; b = -4; c = +41;
Δ = b2-4ac
Δ = -42-4·(-1)·41
Δ = 180
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{180}=\sqrt{36*5}=\sqrt{36}*\sqrt{5}=6\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-6\sqrt{5}}{2*-1}=\frac{4-6\sqrt{5}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+6\sqrt{5}}{2*-1}=\frac{4+6\sqrt{5}}{-2}
$