12(3x-1)=9(3x+1)+15

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Solution for 12(3x-1)=9(3x+1)+15 equation: 



12(3x-1)=9(3x+1)+15

We move all terms to the left:

12(3x-1)-(9(3x+1)+15)=0

We multiply parentheses

36x-(9(3x+1)+15)-12=0



We calculate terms in parentheses: -(9(3x+1)+15), so:

9(3x+1)+15

We multiply parentheses

27x+9+15

We add all the numbers together, and all the variables

27x+24

Back to the equation:

-(27x+24)



We get rid of parentheses

36x-27x-24-12=0

We add all the numbers together, and all the variables

9x-36=0

We move all terms containing x to the left, all other terms to the right

9x=36

x=36/9

x=4

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