296=4x2+140x

Solution for 296=4x2+140x equation:

296=4x^2+140x

We move all terms to the left:

296-(4x^2+140x)=0

We get rid of parentheses

-4x^2-140x+296=0

a = -4; b = -140; c = +296;
Δ = b2-4ac
Δ = -1402-4·(-4)·296
Δ = 24336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{24336}=156$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-140)-156}{2*-4}=\frac{-16}{-8}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-140)+156}{2*-4}=\frac{296}{-8}
=-37
$