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10(x+4)-4=2(3x+1)-3
We move all terms to the left:
10(x+4)-4-(2(3x+1)-3)=0
We multiply parentheses
10x-(2(3x+1)-3)+40-4=0
We calculate terms in parentheses: -(2(3x+1)-3), so:We add all the numbers together, and all the variables
2(3x+1)-3
We multiply parentheses
6x+2-3
We add all the numbers together, and all the variables
6x-1
Back to the equation:
-(6x-1)
10x-(6x-1)+36=0
We get rid of parentheses
10x-6x+1+36=0
We add all the numbers together, and all the variables
4x+37=0
We move all terms containing x to the left, all other terms to the right
4x=-37
x=-37/4
x=-9+1/4
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