290=55/5d

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Solution for 290=55/5d equation: 



290=55/5d

We move all terms to the left:

290-(55/5d)=0



Domain of the equation: 5d)!=0

d!=0/1

d!=0

d∈R



We add all the numbers together, and all the variables

-(+55/5d)+290=0

We get rid of parentheses

-55/5d+290=0

We multiply all the terms by the denominator


290*5d-55=0

Wy multiply elements

1450d-55=0

We move all terms containing d to the left, all other terms to the right

1450d=55

d=55/1450

d=11/290

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