290=5/2(54+v)

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Solution for 290=5/2(54+v) equation: 



290=5/2(54+v)

We move all terms to the left:

290-(5/2(54+v))=0



Domain of the equation: 2(54+v))!=0

v∈R



We add all the numbers together, and all the variables

-(5/2(v+54))+290=0

We multiply all the terms by the denominator


-(5+290*2(v+54))=0



We calculate terms in parentheses: -(5+290*2(v+54)), so:

5+290*2(v+54)

determiningTheFunctionDomain
290*2(v+54)+5

Wy multiply elements

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Back to the equation:

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