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5/2x+6=2x-3
We move all terms to the left:
5/2x+6-(2x-3)=0
Domain of the equation: 2x!=0We get rid of parentheses
x!=0/2
x!=0
x∈R
5/2x-2x+3+6=0
We multiply all the terms by the denominator
-2x*2x+3*2x+6*2x+5=0
Wy multiply elements
-4x^2+6x+12x+5=0
We add all the numbers together, and all the variables
-4x^2+18x+5=0
a = -4; b = 18; c = +5;
Δ = b2-4ac
Δ = 182-4·(-4)·5
Δ = 404
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{404}=\sqrt{4*101}=\sqrt{4}*\sqrt{101}=2\sqrt{101}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-2\sqrt{101}}{2*-4}=\frac{-18-2\sqrt{101}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+2\sqrt{101}}{2*-4}=\frac{-18+2\sqrt{101}}{-8} $
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