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29.4r^2-48.2r-17.4=0
a = 29.4; b = -48.2; c = -17.4;
Δ = b2-4ac
Δ = -48.22-4·29.4·(-17.4)
Δ = 4369.48
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48.2)-\sqrt{4369.48}}{2*29.4}=\frac{48.2-\sqrt{4369.48}}{58.8} $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48.2)+\sqrt{4369.48}}{2*29.4}=\frac{48.2+\sqrt{4369.48}}{58.8} $
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