28x-10-10-16x=3(4x-4)+2

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Solution for 28x-10-10-16x=3(4x-4)+2 equation: 



28x-10-10-16x=3(4x-4)+2

We move all terms to the left:

28x-10-10-16x-(3(4x-4)+2)=0

We add all the numbers together, and all the variables

12x-(3(4x-4)+2)-20=0



We calculate terms in parentheses: -(3(4x-4)+2), so:

3(4x-4)+2

We multiply parentheses

12x-12+2

We add all the numbers together, and all the variables

12x-10

Back to the equation:

-(12x-10)



We get rid of parentheses

12x-12x+10-20=0

We add all the numbers together, and all the variables

-10!=0

There is no solution for this equation

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