(2/3)y-9=(7/3)y-19

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Solution for (2/3)y-9=(7/3)y-19 equation: 



(2/3)y-9=(7/3)y-19

We move all terms to the left:

(2/3)y-9-((7/3)y-19)=0



Domain of the equation: 3)y!=0

y!=0/1

y!=0

y∈R





Domain of the equation: 3)y-19)!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

(+2/3)y-((+7/3)y-19)-9=0

We multiply parentheses

2y^2-((+7/3)y-19)-9=0

We multiply all the terms by the denominator


2y^2*3)y-19)-((-9*3)y-19)+7=0

We add all the numbers together, and all the variables

2y^2*3)y-19)-((-27)y-19)+7=0

Wy multiply elements

6y^3-27)y-19)+7=0

We do not support eypression: y^3

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