If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2/9k+4/3=8+9/8k
We move all terms to the left:
2/9k+4/3-(8+9/8k)=0
Domain of the equation: 9k!=0
k!=0/9
k!=0
k∈R
Domain of the equation: 8k)!=0We add all the numbers together, and all the variables
k!=0/1
k!=0
k∈R
2/9k-(9/8k+8)+4/3=0
We get rid of parentheses
2/9k-9/8k-8+4/3=0
We calculate fractions
2304k^2/648k^2+144k/648k^2+(-729k)/648k^2-8=0
We multiply all the terms by the denominator
2304k^2+144k+(-729k)-8*648k^2=0
Wy multiply elements
2304k^2-5184k^2+144k+(-729k)=0
We get rid of parentheses
2304k^2-5184k^2+144k-729k=0
We add all the numbers together, and all the variables
-2880k^2-585k=0
a = -2880; b = -585; c = 0;
Δ = b2-4ac
Δ = -5852-4·(-2880)·0
Δ = 342225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{342225}=585$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-585)-585}{2*-2880}=\frac{0}{-5760} =0 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-585)+585}{2*-2880}=\frac{1170}{-5760} =-13/64 $
| 3(x-4)+4(x+2)=24 | | 1+8(x-7)=-51-(10-2x) | | x2=4(x–3)2 | | 8.8-2x=5.6 | | 0.8t^2-4t+2.5=0 | | 1/4(12−4x)=3−x | | 1/4(12−4x)=3−x | | -8(k+1)-k-12=-9(k+5)+25 | | -8(k+1)-k-12=-9(k | | 3(x-8)=50 | | 8(3)^x=99 | | 324x=6846x/27 | | b/4−2=4 | | 0.05(3−x)+0.1x=0.24 | | 8=-2(h-89) | | 8=–2(h−89) | | x(0.05)(1)+(271+x)(0.08)(1)=5000 | | b/6+50=58 | | x(0.5)(1)+(271+x)(0.08)(1)=5000 | | 9=u-49/5 | | −23=3x−8 | | 9=u−49/5 | | -3(k-95)=-12 | | 3(k-95)=12 | | 72m^2-30m=0 | | 3(k−95)=12 | | 3(k−95)=–12 | | –3(k−95)=–12 | | s-51/7=4 | | -3(x—2)=-36 | | g-27/8=5 | | (2x-1/2)(10-2x)=0 |