28=b-1+8b

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Solution for 28=b-1+8b equation: 



28=b-1+8b

We move all terms to the left:

28-(b-1+8b)=0

We add all the numbers together, and all the variables

-(9b-1)+28=0

We get rid of parentheses

-9b+1+28=0

We add all the numbers together, and all the variables

-9b+29=0

We move all terms containing b to the left, all other terms to the right

-9b=-29

b=-29/-9

b=3+2/9

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