3y+4(y-2)=6

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Solution for 3y+4(y-2)=6 equation: 



3y+4(y-2)=6

We move all terms to the left:

3y+4(y-2)-(6)=0

We multiply parentheses

3y+4y-8-6=0

We add all the numbers together, and all the variables

7y-14=0

We move all terms containing y to the left, all other terms to the right

7y=14

y=14/7

y=2

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