28=6(v+2)-8v

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Solution for 28=6(v+2)-8v equation: 



28=6(v+2)-8v

We move all terms to the left:

28-(6(v+2)-8v)=0



We calculate terms in parentheses: -(6(v+2)-8v), so:

6(v+2)-8v

We add all the numbers together, and all the variables

-8v+6(v+2)

We multiply parentheses

-8v+6v+12

We add all the numbers together, and all the variables

-2v+12

Back to the equation:

-(-2v+12)



We get rid of parentheses

2v-12+28=0

We add all the numbers together, and all the variables

2v+16=0

We move all terms containing v to the left, all other terms to the right

2v=-16

v=-16/2

v=-8

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