B+8+2b=2(3b+4+23)

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Solution for B+8+2b=2(3b+4+23) equation: 



+8+2B=2(3B+4+23)

We move all terms to the left:

+8+2B-(2(3B+4+23))=0

We add all the numbers together, and all the variables

2B-(2(3B+27))+8=0



We calculate terms in parentheses: -(2(3B+27)), so:

2(3B+27)

We multiply parentheses

6B+54

Back to the equation:

-(6B+54)



We get rid of parentheses

2B-6B-54+8=0

We add all the numbers together, and all the variables

-4B-46=0

We move all terms containing B to the left, all other terms to the right

-4B=46

B=46/-4

B=-11+1/2

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