28=2w+2(w+3)

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Solution for 28=2w+2(w+3) equation:



28=2w+2(w+3)
We move all terms to the left:
28-(2w+2(w+3))=0
We calculate terms in parentheses: -(2w+2(w+3)), so:
2w+2(w+3)
We multiply parentheses
2w+2w+6
We add all the numbers together, and all the variables
4w+6
Back to the equation:
-(4w+6)
We get rid of parentheses
-4w-6+28=0
We add all the numbers together, and all the variables
-4w+22=0
We move all terms containing w to the left, all other terms to the right
-4w=-22
w=-22/-4
w=5+1/2

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