5(5y+2)+23=13-(2y+4)

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Solution for 5(5y+2)+23=13-(2y+4) equation: 



5(5y+2)+23=13-(2y+4)

We move all terms to the left:

5(5y+2)+23-(13-(2y+4))=0

We multiply parentheses

25y-(13-(2y+4))+10+23=0



We calculate terms in parentheses: -(13-(2y+4)), so:

13-(2y+4)

determiningTheFunctionDomain
-(2y+4)+13

We get rid of parentheses

-2y-4+13

We add all the numbers together, and all the variables

-2y+9

Back to the equation:

-(-2y+9)



We add all the numbers together, and all the variables

25y-(-2y+9)+33=0

We get rid of parentheses

25y+2y-9+33=0

We add all the numbers together, and all the variables

27y+24=0

We move all terms containing y to the left, all other terms to the right

27y=-24

y=-24/27

y=-8/9

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