28=2(v+5)-5v

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Solution for 28=2(v+5)-5v equation: 



28=2(v+5)-5v

We move all terms to the left:

28-(2(v+5)-5v)=0



We calculate terms in parentheses: -(2(v+5)-5v), so:

2(v+5)-5v

We add all the numbers together, and all the variables

-5v+2(v+5)

We multiply parentheses

-5v+2v+10

We add all the numbers together, and all the variables

-3v+10

Back to the equation:

-(-3v+10)



We get rid of parentheses

3v-10+28=0

We add all the numbers together, and all the variables

3v+18=0

We move all terms containing v to the left, all other terms to the right

3v=-18

v=-18/3

v=-6

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