6x-2(x+3)=1-3(x+4)

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Solution for 6x-2(x+3)=1-3(x+4) equation: 



6x-2(x+3)=1-3(x+4)

We move all terms to the left:

6x-2(x+3)-(1-3(x+4))=0

We multiply parentheses

6x-2x-(1-3(x+4))-6=0



We calculate terms in parentheses: -(1-3(x+4)), so:

1-3(x+4)

determiningTheFunctionDomain
-3(x+4)+1

We multiply parentheses

-3x-12+1

We add all the numbers together, and all the variables

-3x-11

Back to the equation:

-(-3x-11)



We add all the numbers together, and all the variables

4x-(-3x-11)-6=0

We get rid of parentheses

4x+3x+11-6=0

We add all the numbers together, and all the variables

7x+5=0

We move all terms containing x to the left, all other terms to the right

7x=-5

x=-5/7

x=-5/7

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