28=-4(1-x)+5(x+1)

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Solution for 28=-4(1-x)+5(x+1) equation: 



28=-4(1-x)+5(x+1)

We move all terms to the left:

28-(-4(1-x)+5(x+1))=0

We add all the numbers together, and all the variables

-(-4(-1x+1)+5(x+1))+28=0



We calculate terms in parentheses: -(-4(-1x+1)+5(x+1)), so:

-4(-1x+1)+5(x+1)

We multiply parentheses

4x+5x-4+5

We add all the numbers together, and all the variables

9x+1

Back to the equation:

-(9x+1)



We get rid of parentheses

-9x-1+28=0

We add all the numbers together, and all the variables

-9x+27=0

We move all terms containing x to the left, all other terms to the right

-9x=-27

x=-27/-9

x=+3

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