3(2x-2)-5=3(x-4)+10

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Solution for 3(2x-2)-5=3(x-4)+10 equation: 



3(2x-2)-5=3(x-4)+10

We move all terms to the left:

3(2x-2)-5-(3(x-4)+10)=0

We multiply parentheses

6x-(3(x-4)+10)-6-5=0



We calculate terms in parentheses: -(3(x-4)+10), so:

3(x-4)+10

We multiply parentheses

3x-12+10

We add all the numbers together, and all the variables

3x-2

Back to the equation:

-(3x-2)



We add all the numbers together, and all the variables

6x-(3x-2)-11=0

We get rid of parentheses

6x-3x+2-11=0

We add all the numbers together, and all the variables

3x-9=0

We move all terms containing x to the left, all other terms to the right

3x=9

x=9/3

x=3

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