28=(2x-1)+(x+5)

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Solution for 28=(2x-1)+(x+5) equation: 



28=(2x-1)+(x+5)

We move all terms to the left:

28-((2x-1)+(x+5))=0



We calculate terms in parentheses: -((2x-1)+(x+5)), so:

(2x-1)+(x+5)

We get rid of parentheses

2x+x-1+5

We add all the numbers together, and all the variables

3x+4

Back to the equation:

-(3x+4)



We get rid of parentheses

-3x-4+28=0

We add all the numbers together, and all the variables

-3x+24=0

We move all terms containing x to the left, all other terms to the right

-3x=-24

x=-24/-3

x=+8

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