6(v+2)-2v=2(2v+3)-9

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Solution for 6(v+2)-2v=2(2v+3)-9 equation: 



6(v+2)-2v=2(2v+3)-9

We move all terms to the left:

6(v+2)-2v-(2(2v+3)-9)=0

We add all the numbers together, and all the variables

-2v+6(v+2)-(2(2v+3)-9)=0

We multiply parentheses

-2v+6v-(2(2v+3)-9)+12=0



We calculate terms in parentheses: -(2(2v+3)-9), so:

2(2v+3)-9

We multiply parentheses

4v+6-9

We add all the numbers together, and all the variables

4v-3

Back to the equation:

-(4v-3)



We add all the numbers together, and all the variables

4v-(4v-3)+12=0

We get rid of parentheses

4v-4v+3+12=0

We add all the numbers together, and all the variables

15!=0

There is no solution for this equation

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