28-(n-2)=6(n+4)

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Solution for 28-(n-2)=6(n+4) equation: 



28-(n-2)=6(n+4)

We move all terms to the left:

28-(n-2)-(6(n+4))=0

We get rid of parentheses

-n-(6(n+4))+2+28=0



We calculate terms in parentheses: -(6(n+4)), so:

6(n+4)

We multiply parentheses

6n+24

Back to the equation:

-(6n+24)



We add all the numbers together, and all the variables

-1n-(6n+24)+30=0

We get rid of parentheses

-1n-6n-24+30=0

We add all the numbers together, and all the variables

-7n+6=0

We move all terms containing n to the left, all other terms to the right

-7n=-6

n=-6/-7

n=6/7

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