2x-1=(3/4X)+9=

Solution for 2x-1=(3/4X)+9= equation:

2x-1=(3/4x)+9=

We move all terms to the left:

2x-1-((3/4x)+9)=0


Domain of the equation: 4x)+9)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

2x-((+3/4x)+9)-1=0

We multiply all the terms by the denominator


2x*4x)+9)-((-1*4x)+9)+3=0

Wy multiply elements

8x^2-4x=0

a = 8; b = -4; c = 0;
Δ = b2-4ac
Δ = -42-4·8·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4}{2*8}=\frac{0}{16}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4}{2*8}=\frac{8}{16}
=1/2
$