28+5r=3(5r-2)+7r

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Solution for 28+5r=3(5r-2)+7r equation: 



28+5r=3(5r-2)+7r

We move all terms to the left:

28+5r-(3(5r-2)+7r)=0



We calculate terms in parentheses: -(3(5r-2)+7r), so:

3(5r-2)+7r

We add all the numbers together, and all the variables

7r+3(5r-2)

We multiply parentheses

7r+15r-6

We add all the numbers together, and all the variables

22r-6

Back to the equation:

-(22r-6)



We get rid of parentheses

5r-22r+6+28=0

We add all the numbers together, and all the variables

-17r+34=0

We move all terms containing r to the left, all other terms to the right

-17r=-34

r=-34/-17

r=+2

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