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2(x-4)=5(x+x)
We move all terms to the left:
2(x-4)-(5(x+x))=0
We add all the numbers together, and all the variables
2(x-4)-(5(+2x))=0
We multiply parentheses
2x-(5(+2x))-8=0
We calculate terms in parentheses: -(5(+2x)), so:We add all the numbers together, and all the variables
5(+2x)
We multiply parentheses
10x
Back to the equation:
-(10x)
-8x-8=0
We move all terms containing x to the left, all other terms to the right
-8x=8
x=8/-8
x=-1
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