28(z-1)=3z

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Solution for 28(z-1)=3z equation: 



28(z-1)=3z

We move all terms to the left:

28(z-1)-(3z)=0

We add all the numbers together, and all the variables

-3z+28(z-1)=0

We multiply parentheses

-3z+28z-28=0

We add all the numbers together, and all the variables

25z-28=0

We move all terms containing z to the left, all other terms to the right

25z=28

z=28/25

z=1+3/25

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