2y-5+3y=4(y-1)+4

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Solution for 2y-5+3y=4(y-1)+4 equation:



2y-5+3y=4(y-1)+4
We move all terms to the left:
2y-5+3y-(4(y-1)+4)=0
We add all the numbers together, and all the variables
5y-(4(y-1)+4)-5=0
We calculate terms in parentheses: -(4(y-1)+4), so:
4(y-1)+4
We multiply parentheses
4y-4+4
We add all the numbers together, and all the variables
4y
Back to the equation:
-(4y)
We add all the numbers together, and all the variables
y-5=0
We move all terms containing y to the left, all other terms to the right
y=5

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