28(2x-1)=7(x+3)

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Solution for 28(2x-1)=7(x+3) equation: 



28(2x-1)=7(x+3)

We move all terms to the left:

28(2x-1)-(7(x+3))=0

We multiply parentheses

56x-(7(x+3))-28=0



We calculate terms in parentheses: -(7(x+3)), so:

7(x+3)

We multiply parentheses

7x+21

Back to the equation:

-(7x+21)



We get rid of parentheses

56x-7x-21-28=0

We add all the numbers together, and all the variables

49x-49=0

We move all terms containing x to the left, all other terms to the right

49x=49

x=49/49

x=1

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