(11x-5)+(67)+(9x-15)+(6x+13)+(61)+(4x+29)=1440

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Solution for (11x-5)+(67)+(9x-15)+(6x+13)+(61)+(4x+29)=1440 equation: 



(11x-5)+(67)+(9x-15)+(6x+13)+(61)+(4x+29)=1440

We move all terms to the left:

(11x-5)+(67)+(9x-15)+(6x+13)+(61)+(4x+29)-(1440)=0

We add all the numbers together, and all the variables

(11x-5)+(9x-15)+(6x+13)+(4x+29)-1312=0

We get rid of parentheses

11x+9x+6x+4x-5-15+13+29-1312=0

We add all the numbers together, and all the variables

30x-1290=0

We move all terms containing x to the left, all other terms to the right

30x=1290

x=1290/30

x=43

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