27y-15=3(9y-5)

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Solution for 27y-15=3(9y-5) equation: 



27y-15=3(9y-5)

We move all terms to the left:

27y-15-(3(9y-5))=0



We calculate terms in parentheses: -(3(9y-5)), so:

3(9y-5)

We multiply parentheses

27y-15

Back to the equation:

-(27y-15)



We get rid of parentheses

27y-27y+15-15=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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