-4y(y-2)=12

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Solution for -4y(y-2)=12 equation:



-4y(y-2)=12
We move all terms to the left:
-4y(y-2)-(12)=0
We multiply parentheses
-4y^2+8y-12=0
a = -4; b = 8; c = -12;
Δ = b2-4ac
Δ = 82-4·(-4)·(-12)
Δ = -128
Delta is less than zero, so there is no solution for the equation

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