27=3c-6(6-2c)

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Solution for 27=3c-6(6-2c) equation: 



27=3c-6(6-2c)

We move all terms to the left:

27-(3c-6(6-2c))=0

We add all the numbers together, and all the variables

-(3c-6(-2c+6))+27=0



We calculate terms in parentheses: -(3c-6(-2c+6)), so:

3c-6(-2c+6)

We multiply parentheses

3c+12c-36

We add all the numbers together, and all the variables

15c-36

Back to the equation:

-(15c-36)



We get rid of parentheses

-15c+36+27=0

We add all the numbers together, and all the variables

-15c+63=0

We move all terms containing c to the left, all other terms to the right

-15c=-63

c=-63/-15

c=4+1/5

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