-3(2x-6)+5(3x-4)=16

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Solution for -3(2x-6)+5(3x-4)=16 equation: 



-3(2x-6)+5(3x-4)=16

We move all terms to the left:

-3(2x-6)+5(3x-4)-(16)=0

We multiply parentheses

-6x+15x+18-20-16=0

We add all the numbers together, and all the variables

9x-18=0

We move all terms containing x to the left, all other terms to the right

9x=18

x=18/9

x=2

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