27=3+2(7+2t)

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Solution for 27=3+2(7+2t) equation: 



27=3+2(7+2t)

We move all terms to the left:

27-(3+2(7+2t))=0

We add all the numbers together, and all the variables

-(3+2(2t+7))+27=0



We calculate terms in parentheses: -(3+2(2t+7)), so:

3+2(2t+7)

determiningTheFunctionDomain
2(2t+7)+3

We multiply parentheses

4t+14+3

We add all the numbers together, and all the variables

4t+17

Back to the equation:

-(4t+17)



We get rid of parentheses

-4t-17+27=0

We add all the numbers together, and all the variables

-4t+10=0

We move all terms containing t to the left, all other terms to the right

-4t=-10

t=-10/-4

t=2+1/2

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