39-2(y+1)=3(2y-1)

Solution for 39-2(y+1)=3(2y-1) equation:

39-2(y+1)=3(2y-1)

We move all terms to the left:

39-2(y+1)-(3(2y-1))=0

We multiply parentheses

-2y-(3(2y-1))-2+39=0


We calculate terms in parentheses: -(3(2y-1)), so:

3(2y-1)

We multiply parentheses

6y-3

Back to the equation:

-(6y-3)


We add all the numbers together, and all the variables

-2y-(6y-3)+37=0

We get rid of parentheses

-2y-6y+3+37=0

We add all the numbers together, and all the variables

-8y+40=0

We move all terms containing y to the left, all other terms to the right

-8y=-40

y=-40/-8

y=+5