27=3(x+5)3x

Solution for 27=3(x+5)3x equation:

27=3(x+5)3x

We move all terms to the left:

27-(3(x+5)3x)=0


We calculate terms in parentheses: -(3(x+5)3x), so:

3(x+5)3x

We multiply parentheses

9x^2+45x

Back to the equation:

-(9x^2+45x)


We get rid of parentheses

-9x^2-45x+27=0

a = -9; b = -45; c = +27;
Δ = b2-4ac
Δ = -452-4·(-9)·27
Δ = 2997
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2997}=\sqrt{81*37}=\sqrt{81}*\sqrt{37}=9\sqrt{37}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-9\sqrt{37}}{2*-9}=\frac{45-9\sqrt{37}}{-18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+9\sqrt{37}}{2*-9}=\frac{45+9\sqrt{37}}{-18}
$