27=3(2c+5)

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Solution for 27=3(2c+5) equation: 



27=3(2c+5)

We move all terms to the left:

27-(3(2c+5))=0



We calculate terms in parentheses: -(3(2c+5)), so:

3(2c+5)

We multiply parentheses

6c+15

Back to the equation:

-(6c+15)



We get rid of parentheses

-6c-15+27=0

We add all the numbers together, and all the variables

-6c+12=0

We move all terms containing c to the left, all other terms to the right

-6c=-12

c=-12/-6

c=+2

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